Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    The oxidation states of sulphur in the anions \[SO_{3}^{2-},{{S}_{2}}O_{4}^{2-}\] and \[{{S}_{2}}O_{6}^{2-}\] follow the order

    A)  \[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}\]

    B)  \[SO_{3}^{2-}<{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}\]

    C)  \[{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}<SO_{3}^{2-}\]

    D)  \[{{S}_{2}}O_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}\]

    Correct Answer: A

    Solution :

    Let us consider oxidation number of S is x  In \[SO_{3}^{2-},\] oxidation number of S, \[\Rightarrow \]               \[x+(-2)\times 3=-2\] \[\Rightarrow \]               \[x=-2+6\] \[\therefore \]  \[x=+4\] In \[{{S}_{2}}O_{4}^{2-}\] oxidation number of S \[\Rightarrow \]               \[2\times x+(-2)\times 4=-2\] \[\Rightarrow \]               \[2x=-2+8\] \[\therefore \]  \[x=+3\] In \[{{S}_{2}}O_{6}^{2-}\]-oxidation number of S                 \[\Rightarrow \]               \[2x+(-2)\times 6=-2\] \[\Rightarrow \]               \[2x=-2+12\] \[\therefore \]  \[x=+5\]


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