A) \[X{{Y}_{3}}\]
B) \[{{X}_{3}}Y\]
C) \[XY\]
D) \[X{{Y}_{2}}\]
Correct Answer: A
Solution :
As atoms X are present at the eight corners of the cube, therefore, number of atoms of X in the unit cell \[=\frac{1}{8}\times 8=1\] As atoms Y are present at the face centres of the 6 faces of the cube, therefore, number of atoms of V in the unit cell \[=\frac{1}{2}\times 6=3\] Hence, the formula of compound is \[X{{Y}_{3}}\]
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