2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    A ball is thrown from a point with a speed \[{{v}_{0}}\]at an angle of projection \[\text{ }\!\!\theta\!\!\text{ }\text{.}\]From the same point and at the same instant, a person starts running with a constant speed \[\frac{{{v}_{0}}}{2}\]to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection?

    A) \[\text{Yes,6}{{\text{0}}^{\text{o}}}\]                  

    B) \[\text{Yes,}\,\text{3}{{\text{0}}^{\text{o}}}\]

    C) \[\text{No}\]                                    

    D) \[\text{Yes,}\,{{45}^{\text{o}}}\]

    Correct Answer: A

    Solution :

    Man will catch the ball if the horizontal component of velocity becomes equal to the constant speed of man ie, \[{{v}_{0}}\,\cos \theta =\frac{{{v}_{0}}}{2}\]                 \[\Rightarrow \]               \[\cos \theta =\frac{1}{2}\]                 \[\Rightarrow \]               \[\cos \theta =\cos {{60}^{o}}\]                 \[\therefore \]  \[\theta ={{60}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner