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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    A particle starting from the origin (0, 0) moves in a straight line in the \[(x,y)\] plane. Its coordinates at a later time are \[(\sqrt{3},3).\] The path of the particle makes with the x-axis an angle of

    A) \[30{}^\circ \]

    B) \[45{}^\circ \]

    C) \[60{}^\circ \]

    D) \[0{}^\circ \]

    Correct Answer: C

    Solution :

    Key Idea Slope of the path of the particle gives the measure of angle required. Draw the situation as  shown. OA represents   the path of the particle  starting  from  origin O (0,0).    Draw    a  perpendicular    from  point A to x-axis. Let  path of the particle makes an angle \[\theta \] with the x-axis, then\[\tan \theta \]= slope of line OA \[=\frac{AB}{OB}=\frac{3}{\sqrt{3}}=\sqrt{3}\]                 or            \[\theta ={{60}^{o}}\]


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