2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    A \[0.5\text{ }g/L\]solution of glucose is found to be isotonic with a \[2.5\text{ }g/L\]solution of an organ:: compound. What will be the molecular weight  of that organic compound?

    A)  \[300\]                                

    B)  \[600\]

    C)  \[900\]                                

    D)  \[200\]

    Correct Answer: C

    Solution :

    Molarity of glucose solution \[=\frac{0.5g}{180\times 1L}=0.00277M\] Isotonic   solution   have   equal   molar concentrations, hence molarity of organic compound solution \[\,=0.00277\text{ }M\] \[\therefore \]  Molecular weight of compound                                                                 \[=\frac{2.5}{0.0027\times 1}=900\]


You need to login to perform this action.
You will be redirected in 3 sec spinner