A) \[S{{O}_{2}}\]and \[C{{l}_{2}}\]
B) \[CO\]and \[C{{l}_{2}}\]
C) \[N{{H}_{3}}\]and \[S{{O}_{2}}\]
D) \[{{H}_{2}}S\]and \[B{{r}_{2}}\]
Correct Answer: A
Solution :
The bleaching action of \[S{{O}_{2}}\] is due to reduction . while the bleaching action of \[C{{l}_{2}}\] is due to oxidation.
You need to login to perform this action.
You will be redirected in
3 sec
