A) \[H{{g}^{2+}}\]
B) \[B{{i}^{3+}}\]
C) \[P{{b}^{2+}}\]
D) \[C{{u}^{+}}\]
Correct Answer: B
Solution :
Since, the metal nitrate gives black ppt with \[KI\]which in excess of \[KI\] turns into orange, the metal must be \[B{{i}^{3+}}\] and the reactions are as follows \[B{{i}^{3+}}+3{{I}^{-}}\xrightarrow{{}}\underset{black}{\mathop{Bi{{I}_{3}}}}\,\downarrow \] \[Bi{{I}_{3}}+{{I}^{-}}\underset{orange\,colour}{\mathop{{{[Bi{{I}_{4}}]}^{-}}}}\,\]
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