Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    If one mole of a monoatomic gas \[\left( y=\frac{5}{3} \right)\] is mixed with one mole of a diatomic gas \[\left( y=\frac{7}{3} \right),\] the value of y for the mixture is

    A)  1.40                                      

    B)  1.50

    C)  1.53                                      

    D)  3.07

    Correct Answer: D

    Solution :

    \[{{\gamma }_{mix}}=\frac{\frac{\mu {{ & }_{1}}{{\gamma }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}{{\gamma }_{2}}}{{{\gamma }_{2}}-1}}{\frac{{{\mu }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}}{{{\gamma }_{2}}-1}}\] \[\frac{\frac{1\times \frac{5}{3}}{\left( \frac{5}{3}-1 \right)}+\frac{1\times \frac{7}{3}}{\left( \frac{7}{3}-1 \right)}}{\frac{1}{\left( \frac{5}{3}-1 \right)}+\frac{1}{\left( \frac{7}{5}-1 \right)}}\approx 1.06\] Hence, no option is matching.


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