A) \[8,2\]
B) \[2,8\]
C) \[4,2\]
D) \[2,4\]
Correct Answer: A
Solution :
The molecular orbital configuration of \[CO\] is as \[CO(6+8=14)\] \[=K{{K}^{*}}\,\,\sigma 2{{s}^{2}},\sigma *2{{s}^{2}},\pi 2p_{x}^{2}\approx \pi 2p_{y}^{2},\sigma 2p_{z}^{2}\] (* = antibonding orbitals) Number of bonding electrons = 8 Number of antibonding electrons = 2
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