A) \[3.0\times {{10}^{20}}\]
B) \[1.5\times {{10}^{20}}\]
C) \[1.6\times {{10}^{19}}\]
D) \[3.2\times {{10}^{19}}\]
Correct Answer: A
Solution :
Charge \[q=it\] To remove N ions, required necessary charge is \[Q=Nq\] Charge of \[C{{u}^{2+}},\] \[q=2e\] From \[N(2e)=it\] \[N(2\times 1.6\times {{10}^{-19}})=1.6\times 60\] \[N=3\times {{10}^{20}}\]
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