A) \[1500\]
B) \[10000\]
C) \[2.4\times {{10}^{5}}\]
D) \[2\times {{10}^{12}}\]
Correct Answer: C
Solution :
Given, weight of \[PVC,\text{ }w=4\text{ }g\] Volume of solution, \[V=1\text{ }L\] Osmotic pressure, \[\pi =4.1\times {{10}^{-4}}\] Temperature, \[T={{27}^{o}}C=27+273=300\text{ }K\] \[\because \] \[\pi V=nRT\] or \[\pi V=\frac{w}{M}RT\] (.M = molecular weight) \[4.1\times {{10}^{-4}}\times 1=\frac{4}{M}\times 0.0821\times 300\] \[M=\frac{4\times 0.0821\times 300}{4\times {{10}^{-4}}\times 1}\] \[\therefore \] \[M=2.4\times {{10}^{5}}\]
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