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CMC Medical CMC-Medical Ludhiana Solved Paper-2015

  • question_answer
    What will be the product when \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]reacts with cone. \[{{H}_{2}}S{{O}_{4}},\] i.e.\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+2{{H}_{2}}S{{O}_{4}}\xrightarrow{Cold}\]

    A)  \[C{{r}_{2}}{{O}_{3}}\]                 

    B)  \[Cr{{O}_{3}}\]

    C)  \[C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\]                            

    D)  Both (a) and (b)

    Correct Answer: B

    Solution :

    \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+2{{H}_{2}}S{{O}_{4}}\xrightarrow{Cold}\]\[2Cr{{O}_{3}}+2KHS{{O}_{4}}+{{H}_{2}}O\]\[Cr{{O}_{3}}\]also called chromic acid. It is highly acidic and oxidizing agent.


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