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CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    A car of mass m is moving with momentum P. If\[\mu \]be the coefficient of friction between the tyres and the road, what will be stoppin distance due to friction alone?

    A)  \[\frac{{{P}^{2}}}{2\mu g}\]                      

    B)  \[\frac{{{P}^{2}}}{2\,m\mu g}\]

    C)  \[\frac{{{P}^{2}}}{2\,{{m}^{2}}\mu g}\]                

    D)  \[\frac{{{P}^{2}}}{2\,mg}\]

    Correct Answer: C

    Solution :

                    If the car stops after covering distance, then \[F\times s=\frac{{{P}^{2}}}{2m}\] \[\mu mg\times s=\frac{{{P}^{2}}}{2m}\] \[\]


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