CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    The ratio of intensity at the centre of a bright fringe to the intensity at a point distant one fourth of the distance between two successive bright fringes will be

    A)  4                                            

    B)  3   

    C)  2                                            

    D)  1

    Correct Answer: C

    Solution :

                    \[{{I}_{0}}=I+I+2\sqrt{II}\cos 0{}^\circ \] \[{{I}_{0}}=2I+2I=4I\] Intensity at a point distance\[\frac{\beta }{4}\]is \[I=I+I+2\sqrt{II}\cos \frac{\pi }{2}\] \[I=2I+2\sqrt{II}\times 0\] \[I=2I\] \[\frac{{{I}_{0}}}{I}=\frac{4I}{2I}=2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner