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CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    The oxidation number of\[N\]and\[Cl\]in \[NOCl{{O}_{4}}\] respectively are

    A)  +2 and +7                          

    B)  +3 and +7

    C)  -3 and +7                           

    D)  +2 and -7

    Correct Answer: B

    Solution :

              Oxidation number of\[N\]in\[N{{O}^{+}}\]is \[(1\times x)+1\times (-2)=+1\]           \[x=+\,3\] Oxidation number of\[Cl\]in\[ClO_{4}^{-}\]is \[(1\times x)+4\times (-2)=-1\] \[\therefore \]                  \[x=+7\]


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