A) 1.520
B) 0.995
C) 19.00
D) 9.00
Correct Answer: D
Solution :
\[\frac{\text{Wt}\text{. of metal hydroxide}}{\text{Wt}\text{. of metal oxide}}\] \[\frac{\text{Eq}\text{. wt}\text{.}\,\,\text{of metal}+\text{Eq}\text{.}\,\text{wt}\text{. of}\,O{{H}^{-}}}{\text{Eq}\text{. wt}\text{. of metal}+\text{Eq}\text{. wt}\text{.}\,\,\text{of}\,O_{2}^{2-}}\] \[\Rightarrow \] \[\frac{1.520}{0.995}=\frac{E+17}{E+8}\] On solving, E = 9.0
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