A) 96500 C
B) 5790 C
C) 95700 C
D) 57900 C
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+6{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}{{C}_{6}}{{H}_{5}}N{{H}_{2}}+2{{H}_{2}}O\]1 mol (= 123 g) nitrobenzene requires 6 moles of electrons = 6 x 96500 C charge \[\therefore \] 12.3g nitrobenzene will require charge \[=\frac{6\times 96500\times 12.3}{123}\] \[=6\times 9650=57900\,C\]
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