| I. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] |
| II. \[C{{H}_{3}}CH=CH-C{{H}_{3}}\] |
| III. \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\] |
| IV. \[H-C-C\equiv C-H\] |
A) II and IV
B) I and IV
C) II and III
D) Only II
Correct Answer: D
Solution :
I. \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\]only \[s{{p}^{3}}\]hybridized carbon II. \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\]both \[s{{p}^{2}}\]and \[s{{p}^{3}}\]hybridised carbon. III. \[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\]only \[s{{p}^{2}}\]hybridized carbon. IV. \[H-\overset{sp}{\mathop{C}}\,\equiv \overset{sp}{\mathop{C}}\,-H\]only \[sp\text{-}\]hybridised carbon.
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