A) \[{{K}_{C}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]
B) \[{{K}_{C}}={{[{{O}_{2}}]}^{5}}\]
C) \[{{K}_{C}}=\frac{[{{P}_{4}}{{O}_{10}}]}{5\,[{{P}_{4}}]\,[{{O}_{2}}]}\]
D) \[{{K}_{C}}=\frac{[{{P}_{4}}{{O}_{10}}]}{[{{P}_{4}}]\,{{[{{O}_{2}}]}^{5}}}\]
Correct Answer: A
Solution :
\[{{P}_{4}}(s)+5{{O}_{2}}(g){{P}_{4}}{{O}_{10}}(s)\] \[{{K}_{C}}=\frac{[{{P}_{4}}{{O}_{10}}(s)]}{[{{P}_{4}}(s)]\,{{[{{O}_{2}}(g)]}^{5}}}\] We, know that concentration of a solid component is always taken as unity. \[{{K}_{C}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]
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