CMC Medical CMC-Medical VELLORE Solved Paper-2015

  • question_answer
    A toroid has the radius equal to 10/\[\pi \]cm while number of turns are 400 and carrying a current 2 A. If the magnetisation\[I\]is \[4.8\times {{10}^{-2}}A{{m}^{-1}}\] then, susceptibility is

    A)  \[4.8\times {{10}^{-5}}\]                             

    B)  \[3.9\times {{10}^{-4}}\]

    C)  \[2.7\times {{10}^{-5}}\]                             

    D)  \[5.2\times {{10}^{-4}}\]

    E)  None of these

    Correct Answer: A

    Solution :

                    The number of turns per unit length of toroid is\[n=\frac{400}{2\pi R}\] The magnetic intensity \[H=ni\] \[=\frac{400\times 2}{2\pi \times \frac{10}{\pi }\times {{10}^{-2}}}=1000\,A{{m}^{-1}}\] The susceptibility is \[\chi =I/H=\frac{4.8\times {{10}^{-2}}A{{m}^{-1}}}{1000\,A{{m}^{-1}}}\] \[=4.8\times {{10}^{-5}}\]


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