The combination of three blocks is pushed by a horizontal force of 30 N on frictionless surface. Choose the correct option
A) Force exerted by A on B is 5 N
B) Force exerted by A on B is 15 N
C) Force exerted by C on B is 15 N
D) Force exerted by 6 on A is 10 N
Correct Answer: C
Solution :
As per Newtons law of motion, F = ma Force on B by A, \[=2\times \frac{F}{{{m}_{1}}\times {{m}_{2}}}=2\times \frac{30}{3}=20N\] Force on C by B, \[=3\times \frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] \[=3\times \frac{30}{6}=15\,N\] Thus. force on C by B is 15 N
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