CMC Medical CMC-Medical VELLORE Solved Paper-2015

  • question_answer
    A mass of 5 kg is moving along a circular path of radius 1 m. If the mass moves with 300 revolutins per minute, its kinetic energy would be

    A)  250 \[{{\pi }^{2}}\]                         

    B)  100\[{{\pi }^{2}}\]

    C)  5\[{{\pi }^{2}}\]                                               

    D)  0

    E)  36\[{{\pi }^{2}}\]

    Correct Answer: A

    Solution :

                    Here      \[m=5\,kg,\,\,r=i\,m\] \[w=\frac{300}{60}rps=5\,rps\] \[=5\times 2\pi \,rods\] \[K.E.=\frac{1}{2}m{{v}^{2}}\] \[=\frac{1}{2}m\,{{(rw)}^{2}}\] \[=\frac{1}{2}\times 5\,{{(1\times 10\pi )}^{2}}\] \[=250\,{{\pi }^{2}}J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner