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CMC Medical CMC-Medical VELLORE Solved Paper-2015

  • question_answer
    For a closed organ pipe, the fundamental frequency is equal to first overtone frequency of an open organ pipe. If the length of the open pipe is 60 cm, then length of the closed organ pipe will be

    A)  25 cm                  

    B)  18 cm

    C)  10 cm                  

    D)  111 cm

    E)  15 cm

    Correct Answer: E

    Solution :

                    The fundamental frequency of a closed organ pipe is \[\frac{v}{4{{l}_{1}}}.\] The fundamental frequency of an open organ pipe is \[\frac{v}{4{{l}_{2}}}.\] Here, \[{{l}_{1}}\] = length of closed organ pipe and \[{{l}_{2}}\] = length of the open organ pipe when, \[{{l}_{2}}\] = 60 cm, then in accordance with question \[\frac{v}{4{{l}_{1}}}=\frac{v}{60\,cm}\] \[{{l}_{1}}=\frac{1}{4}\times 60\,cm=15\,cm\]


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