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CMC Medical CMC-Medical VELLORE Solved Paper-2015

  • question_answer
    For a helium ion with one electron and nuclear charge 2q, where q is the charge on a proton. The energy of the state with principal quantum number n = 4, is

    A)  2.4 eV                 

    B)  -8.4 eV

    C)  -7.2 eV                                

    D)  13.2 eV

    E)  -3.4 eV

    Correct Answer: E

    Solution :

                    The energy of state is given as \[E=-\frac{13.6\,{{z}^{2}}}{{{n}^{2}}}=\frac{-13.6}{{{4}^{2}}}\times {{2}^{2}}\]     \[=\frac{-13.6\times 4}{16}=-3.4\,eV\]


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