question_answer

According to Arrhenius equation what will be the effect on log k with increase in\[\frac{1}{T}\]?

A)  Increase linearly

B)  Change exponentially

C)  Decrease linearly

D)  Perabolically change

E)  No change, constant

Correct Answer: C

Solution :

                Decrease linearly, \[k=A{{e}^{-{{E}_{a}}/RT}}\] \[k=\ln A-\frac{{{E}_{a}}}{RT}\] Intercept = ln A Slope = \[-\frac{{{E}_{a}}}{R}\]