A) \[N{{a}^{+}}<A{{l}^{3+}}<M{{g}^{2+}}\]
B) \[A{{l}^{3+}}<M{{g}^{2+}}<N{{a}^{+}}\]
C) \[N{{a}^{+}}<M{{g}^{2+}}<A{{l}^{3+}}\]
D) \[N{{a}^{+}}=M{{g}^{2+}}<A{{l}^{3+}}\]
E) \[N{{a}^{+}}<M{{g}^{2+}}=A{{l}^{3+}}\]
Correct Answer: C
Solution :
Smaller the size of cation, larger the charge, larger the hydration, or we can say that hydration will be more in charge to size ratio. The size of cation will decrease from left to right Charge as given increases from \[N{{a}^{+}}\] to\[A{{l}^{3+}}\]. Therefore, hydration will be maximum for \[A{{l}^{3+}}.\]
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