Haryana PMT Haryana PMT Solved Paper-1999

  • question_answer
    Light travels in two media A (denser) and \[\beta \]B      rarer with speeds \[2\times {{10}^{8}}m/s\]and \[2.4\times {{10}^{8}}m/s\] respectively. The critical angle C-              between them will be :

    A) \[56.4{}^\circ \]                

    B) \[66.4{}^\circ \]

    C) \[46.4{}^\circ \]

    D) \[36.4{}^\circ \]

    Correct Answer: A

    Solution :

                    Using the relation, \[\sin \,C=\frac{{{\mu }_{r}}}{{{\mu }_{d}}}=\frac{\frac{c}{{{\upsilon }_{r}}}}{c/{{\upsilon }_{d}}}=\frac{{{\upsilon }_{d}}}{{{\upsilon }_{r}}}\] \[\sin \,C=\frac{velocity\text{ }in\text{ }denser\text{ }medium}{velocity\text{ }in\text{ }rarer\text{ }medium}\] \[\sin \,C=\frac{2\times {{10}^{8}}}{2.4\times {{10}^{8}}}=\frac{5}{6}\]                 or                            \[C={{\sin }^{-1}}\,\frac{5}{6}\,={{56.4}^{o}}\]


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