A) 50
B) 25
C) 75
D) 40
Correct Answer: A
Solution :
The slope of anode characteristic curve is \[\frac{1}{{{R}_{p}}}=\left( \frac{\Delta {{i}_{p}}}{\Delta {{V}_{p}}} \right)\] \[=0.04\,mA/V\] Plate resistance \[{{R}_{p}}=\frac{1}{0.04\times {{10}^{-3}}}=25\times {{10}^{3}}\Omega \] The slope of mutual characteristic curve is \[{{g}_{m}}=\left( \frac{\Delta {{i}_{p}}}{\Delta {{V}_{g}}} \right)=2.0\,mA/V\] \[=2.0\times {{10}^{-3}}mho\] Amplification factor, \[\mu ={{R}_{p}}\times {{g}_{m}}\] \[=25\times {{10}^{3}}\times 2.0\times {{10}^{-3}}=50\]
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