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Haryana PMT Haryana PMT Solved Paper-1999

  • question_answer
    The   permittivity   of   diamond   is \[1.46\times {{10}^{-10}}{{C}^{2}}/N{{m}^{2}}\] The electric susceptibility  of  diamond  will  be \[({{\varepsilon }_{0}}=8.85\times {{10}^{-12}}{{C}^{2}}/N{{m}^{2}})\]:

    A)  15.5                                      

    B)  16.5

    C)  7.75                                      

    D)  none of these

    Correct Answer: A

    Solution :

                    Dielectric constant is given by as \[K=\frac{\varepsilon }{{{\varepsilon }_{0}}}=\frac{1.46\times {{10}^{-10}}}{8.85\times {{10}^{-12}}}=16.5\] Now, by the relation for susceptibility                 \[K=1+{{X}_{e}}\] or            \[{{X}_{e}}=K-1\]                 \[=16.5-1=15.5\]


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