A) \[{{C}_{2}}{{H}_{2}}\]
B) \[C{{H}_{2}}\]
C) \[{{C}_{3}}{{H}_{8}}\]
D) \[{{C}_{3}}{{H}_{6}}\]
Correct Answer: D
Solution :
Empirical formula weight of \[C{{H}_{2}}=12+(1\times 2)\] \[=12+2\] \[=14\] Mass of 1 mole of the compound = its molecular weight \[=42\] \[n=\frac{molecular\,weight}{empirical\,formula\,weight}\] \[=\frac{42}{14}=3\] \[\therefore \] molecular formula = (empirical formula) \[\times n\] \[=(C{{H}_{2}})\times 3\] \[={{C}_{3}}{{H}_{6}}\]
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