A) \[\frac{373-250}{373}\]
B) \[\frac{275+250}{373}\]
C) \[\frac{100+23}{100}\]
D) \[\frac{373-123}{100}\]
Correct Answer: A
Solution :
Efficiency of Carnot engine is given by \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] Here, \[{{T}_{1}}={{100}^{o}}C=373K\] \[{{T}_{2}}={{23}^{o}}C=250K\] \[\eta =\frac{373-250}{373}\]
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