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Haryana PMT Haryana PMT Solved Paper-2000

  • question_answer
    The internal resistance of a cell of emf \[12\,V\,is\,5\times 10{{-}^{2}}\Omega \]It is connected across an unknown resistance, the voltage across the cell when a current of 60 amp is drawn from it, is :

    A)  10V                                      

    B)  6V

    C)  12 V                                     

    D)  9 V

    Correct Answer: D

    Solution :

                    Using the relation, \[i=\frac{E}{R+r}\] Here,  \[r=5\times {{10}^{-2}}=0.05\Omega ,\,E=12V,\,i=60a\]                 \[60=\frac{12}{R+0.05}\]                 \[=60R+3=12\] So,          \[R=\frac{9}{60}\Omega \] Now, voltage across cell is given by                 \[V=iR=60\times \frac{9}{60}=9V\]


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