Haryana PMT Haryana PMT Solved Paper-2000

  • question_answer
    A black body is heated from \[27{}^\circ C\] to \[927{}^\circ C\]. The ratio of radiation emitted will be :

    A)  1:8                                        

    B)  1:16

    C)  1:128                                   

    D)  1:256

    Correct Answer: D

    Solution :

                    According to Stefans law \[E\propto {{T}^{4}}\] Hence,     \[\frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\]                                    ?..(i) Here,     \[{{T}_{1}}={{27}^{o}}C=300K\]                 \[{{T}_{2}}={{927}^{o}}C=1200K\] From equation (i) we get or            \[\frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{300}{1200} \right)}^{4}}=\frac{1}{256}=1:256\]


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