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Haryana PMT Haryana PMT Solved Paper-2000

  • question_answer
    Water falls from a height 500 m. What is the raise in temperature of water at bottom. If the whole energy remains in the water? (Specific heat of water \[4200\text{ }J/kg\text{ }{}^\circ C\]):

    A) \[0.19{}^\circ C\]

    B) \[2.3{}^\circ C\]

    C) \[0.59{}^\circ C\]

    D) \[1.17{}^\circ C\]

    Correct Answer: D

    Solution :

                    Here:        \[h=500mg\,=9.8m/{{s}^{2}}\] \[c=4200J/k{{g}^{o}}C\] Using the relation                 \[mgh=mc\Delta \theta \] \[m\times 9.8\times 500=m\times 4200\times \Delta \theta \]                 So,          \[\Delta \theta =\frac{9.8\times 500}{4200}\]                                 \[={{1.17}^{o}}C\]


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