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Haryana PMT Haryana PMT Solved Paper-2000

  • question_answer
    Energy required to dissociate \[4g\] of gaseous hydrogen in to free gaseous atoms is \[208kcal\] at \[{{25}^{o}}C\]. The bond energy of \[H-H\] bond will be:

    A)  \[104kcal\]       

    B)  \[104kcal\]

    C)  \[10.4\text{ }kcal\]                        

    D)  \[1040\text{ }kcal\]

    Correct Answer: A

    Solution :

    Sol.         \[2{{H}_{2}}\xrightarrow{{}}4H,\]             \[\Delta H=208kcal\] \[H-H\xrightarrow{{}}2H;\]          \[\Delta H=\frac{208}{2}=104kcal\]


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