A) 4
B) 8
C) 16
D) 32
Correct Answer: A
Solution :
By kinetic theory of gas \[P=\frac{M{{N}^{\frac{2}{c}}}}{3V}\] \[3PV={{M}^{\frac{2}{c}}}\] or \[3RT=M{{c}^{-2}}\], T is constant \[^{\frac{2}{c}}\propto \frac{1}{M}\] or \[\frac{^{\frac{2}{C}}H}{^{\frac{2}{C}}O}=\frac{{{M}_{O}}}{{{M}_{H}}}=\frac{32}{2}\] or \[\frac{^{C}H}{^{C}O}=\sqrt{\frac{16}{1}}=\frac{4}{1}\]
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