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Haryana PMT Haryana PMT Solved Paper-2001

  • question_answer
    300 joule of work is done in sliding a 2 kg block up an inclined plane to a height of 10 m. Taking the value of acceleration due r\ to gravity g to be 10 m/s , work done against friction is :

    A)  zero                                     

    B)  300 joule

    C)  200 joule                            

    D)  100 joule

    Correct Answer: D

    Solution :

                    Work done against gravity \[=mgh\] \[=2\times 10\times 10=200\text{ }joule\] Total work done \[=300joule\] Hence, work done against friction is \[=300-200=100\text{ }joule\]


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