A) \[{{C}_{\omega }}<{{C}_{g}}=0\]
B) \[{{C}_{\omega }}={{C}_{g}}\]
C) \[{{C}_{\omega }}<{{C}_{g}}\]
D) \[{{C}_{\omega }}>{{C}_{g}}\]
Correct Answer: D
Solution :
As refractive index of water \[{{\mu }_{\omega }}=1.33\] and refractive index of glass \[{{\mu }_{g}}=1.5\] The relation for critical angle of water \[\sin {{C}_{\omega }}=\frac{1}{{{\mu }_{\omega }}}=\frac{1}{1.33}=0.75\] or \[{{C}_{\omega }}={{\sin }^{-1}}0.75\] \[{{C}_{\omega }}={{48.6}^{o}}\] ?..(1) Similarly sin \[{{C}_{g}}=\frac{1}{{{\mu }_{g}}}=0.67\] or \[{{C}_{g}}={{\sin }^{-1}}0.67={{42.06}^{o}}\] ??.(2) Hence, It is quite lear from eq (1) and (2) \[{{C}_{\omega }}>{{C}_{g}}\]
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