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Haryana PMT Haryana PMT Solved Paper-2002

  • question_answer
    A straight section \[PQ\] of a circuit lies along x- axis at \[x=-\frac{a}{2}to\,x-+\frac{a}{2}\] and carries a steady                 current (\[i\]), the magnetic field due to section               \[PQ\] at a point \[x=+a\] will be :

    A)  proportional to \[a\]     

    B)  proportional to\[{{a}^{2}}\]

    C)  proportional to \[\frac{1}{a}\]  

    D)  equal to zero

    Correct Answer: D

    Solution :

                    From Biot Savants law magnetic field at                 point R due to a straight wire \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{i\,\Delta \,\sin \theta }{{{r}^{2}}}\] but         \[\theta =0\] \[\therefore \]  \[B=0\]


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