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Haryana PMT Haryana PMT Solved Paper-2002

  • question_answer
    In Youngs double slit experiment, the slits are    0.5 mm apart and interference pattern is observed on a screen placed at a distance of 1m from the place containing the slits. If wavelength of the incident light is \[6000\overset{\text{o}}{\mathop{\text{A}}}\,\] then the separation between the third bright fringe and central maxima is :

    A)  4mm                                    

    B)  3.6 mm

    C)  3 mm                                   

    D)  2.5 mm

    Correct Answer: B

    Solution :

                     Separation between, third-bright fringe and central maxima \[=\frac{3D\lambda }{d}\]                 \[=\frac{3\times 1\times 6\times {{10}^{-7}}}{0.5\times {{10}^{-3}}}\]                 \[=3.6\times {{10}^{-3}}m=3.6mm\]


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