A) two times as that of proton
B) half as that of proton
C) four times as that of proton
D) same as that of proton
Correct Answer: A
Solution :
Time period \[T=\frac{2\pi m}{Bq}\] \[T\propto \frac{m}{q}\] \[\frac{{{T}_{\alpha }}}{{{T}_{p}}}=\left( \frac{m\alpha }{{{m}_{p}}} \right)\left( \frac{{{q}_{p}}}{{{q}_{\alpha }}} \right)\] \[=\left( \frac{4{{m}_{p}}}{{{m}_{p}}} \right)\left( \frac{{{q}_{p}}}{2{{q}_{p}}} \right)\] \[{{T}_{\alpha }}=2{{T}_{p}}\]
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