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Haryana PMT Haryana PMT Solved Paper-2002

  • question_answer
    The half life of a radioactive isotope is 2.5 our. If the initial mass of the isotope was 16 g, the mass of it remain undecayed after 10 hours will be:

    A)  \[32g\]                                

    B)  \[4g\]   

    C)  \[16g\]                                

    D)  \[1g\]

    Correct Answer: D

    Solution :

                    Number of half-lives = n \[=\frac{10}{2.5}=4\] Amount left \[=\frac{Initial\text{ }amount}{{{2}^{n}}}\]                 \[=\frac{16}{24}=\frac{16}{16}=1g\]


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