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Haryana PMT Haryana PMT Solved Paper-2002

  • question_answer
    The half life of a radioactive element is \[3.8\] days. The time at the end of which 1/20th of     the element will remain undecayed will be:   

    A)  \[36\text{ }day\]            

    B)  \[12.86\text{ }day\]

    C)  \[24.20\text{ }day\]                      

    D)  \[16.40\]

    Correct Answer: D

    Solution :

                     Time \[(T)=\frac{2.303\times {{t}^{1/2}}}{0.693}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303\times 3.8}{0.693}\log \left( \frac{{{N}_{0}}}{{{N}_{0}}/20} \right)\]


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