A) 16 day
B) 2 day
C) 4 day
D) 8 day
Correct Answer: D
Solution :
Applying Keplers law \[T\propto {{r}^{3/2}}\] We know that time period of parking orbit is 1 day (given: \[{{T}_{s}}=r\]parking orbit) Hence, \[\frac{{{T}_{s}}}{{{T}_{parking}}}={{\left( \frac{4{{r}_{parking\,orbit}}}{{{r}_{parking\,orbit}}} \right)}^{3/2}}\] \[={{(4)}^{3/2}}=8\] \[{{T}_{s}}=8\times {{T}_{parking}}\] \[=8\times 1=8days\]
You need to login to perform this action.
You will be redirected in
3 sec
