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Haryana PMT Haryana PMT Solved Paper-2003

  • question_answer
    The critical angle for a medium is 45°, the refractive index will be :

    A)  \[\frac{1}{\sqrt{2}}\]                                    

    B)  \[\sqrt{2}\]

    C)  \[\frac{\sqrt{3}}{2}\]                                    

    D) \[\frac{2}{\sqrt{3}}\]

    Correct Answer: B

    Solution :

                    Using the relation \[\mu =\frac{1}{\sin C}=\frac{1}{\sin {{45}^{o}}}\] \[=\frac{1}{1/\sqrt{2}}=\sqrt{2}\]


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