2. Solved Papers
  3. Haryana PMT

Haryana PMT Haryana PMT Solved Paper-2003

  • question_answer
    In an ammeter, 4% of the main current is passing through galvanometer. If the galvanometer is shunted with a 5\[\Omega \] resistance.   The   resistance   of   the galvanometer is :

    A)  120\[\Omega \]              

    B)  20\[\Omega \]

    C)  5 \[\Omega \]                                  

    D)  4 \[\Omega \]

    Correct Answer: A

    Solution :

                    Using the relation \[\frac{G}{S}=\frac{i}{{{i}_{g}}}-1\]  (Here: \[\frac{i}{{{i}_{g}}}=\frac{4}{100}=0.04,\,S=1.5\Omega \] So,          \[\frac{G}{5}=\frac{1}{0.04}-1=24\] \[\Rightarrow \]               \[G=5\times 24=120\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner