A) \[N{{H}_{3}}\]
B) \[{{H}_{2}}O\]
C) \[BC{{l}_{3}}\]
D) none of these
Correct Answer: D
Solution :
\[BC{{l}_{3}}\] has bond-angle equal to \[{{120}^{o}}\] (trigonal planar). \[N{{H}_{3}}\] and \[{{H}_{2}}O\] have \[s{{p}^{3}}\] hybridisation but due to the presence of lone pair of electrons, they have bond angle less than\[{{109}^{o}}28\]. \[(N{{H}_{3}}-{{107}^{o}},\,{{H}_{2}}O-{{104.5}^{o}})\]. \[As{{H}_{3}}\] (\[s{{p}^{3}}\] hybrid) has smaller bond angle than NHs due to less electronegativity of As than N.
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