question_answer

Which hybridisation has sulphur in \[S{{O}_{2}}\]?

A)  \[s{{p}^{2}}\]                                   

B)  \[s{{p}^{3}}{{d}^{2}}\]       

C)  \[s{{p}^{3}}\]                                   

D)  \[sp\]

Correct Answer: A

Solution :

                \[\underset{(lps+\sigma -bps=1+2=3)}{\mathop{O=\overset{\centerdot \centerdot }{\mathop{S}}\,=O}}\,\]hence, hybridisation \[=s{{p}^{2}}\]S in 1st excited state = Hence, \[S{{O}_{2}}\] has angular geometry.