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Haryana PMT Haryana PMT Solved Paper-2003

  • question_answer
    A  \[0.5g/l\]solution of glucose is found to be isotonic with a \[2.5\text{ }g/l\] solution of an organic compound. What will be the molecular weight of that organic compound?

    A)  \[300\]                                

    B)  \[600\]

    C)  \[900\]                                

    D)  \[1200\]

    Correct Answer: C

    Solution :

                    Molarity of glucose solution \[=\frac{0.5g}{180\times 1lit.}\] \[=0.0027M\] Isotonic solution have equal molar concentration, hence molarity of organic compound solution \[=0.0027\text{ }M\] \[\therefore \] Molecular weight of compound                 \[=\frac{2.5}{0.0027\times 1}\]                 \[=900\]


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