Haryana PMT Haryana PMT Solved Paper-2004

  • question_answer
    The speed of sound through oxygen at TK is \[u\] \[m{{s}^{-1}}.\] As the temperature becomes 2T and oxygen gas dissociates into atomic oxygen, the speed of sound :

    A)  remains the same          

    B)  becomes \[2u\]

    C)  becomes \[\sqrt{2u}\]

    D)  none of these

    Correct Answer: B

    Solution :

                                             The rms velocity of sound in gas is \[{{\upsilon }_{rms\,\,(molecules)}}=\sqrt{\frac{\gamma RT}{M}}=\sqrt{\frac{1.4\times RT}{M}}\]   ?.(1) when the oxygen dissociates, its molecular mass becomes atomic mass, so, \[M=\frac{M}{2}\] and \[T=2T\] given and \[\gamma =1.66\] \[{{\upsilon }_{(rms)\,\,(atomic)}}=\sqrt{\frac{1.66\times R\times 2T}{M/2}}\] \[=\sqrt{\frac{1.66\times R\times 2T\times 2}{M}}\]              ???.(2) From equations (1) and (2) \[\frac{{{\upsilon }_{rms\,\,(atomic)}}}{{{\upsilon }_{rms\,(molecular)}}}=\sqrt{\frac{1.66\times R\times 2T\times 2}{M}}\]                                          \[\times \sqrt{\frac{M}{1.4\times RT}}\]                                          \[=\sqrt{\frac{1.66\times 4}{1.4}}=2.18\] Hence,  \[{{\upsilon }_{rms\,(atomic)}}=2.18{{\upsilon }_{rms\,(molecular)}}\]                                          \[\approx 2{{\upsilon }_{rms\,(molecular)}}\]


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